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Mar 8, 2023 at 4:12 vote accept Brian
Mar 7, 2023 at 5:06 history edited Zach Goldthorpe CC BY-SA 4.0
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Mar 7, 2023 at 5:06 comment added Zach Goldthorpe @Maiyu one last edit. I have modified the definition of the norm so that the Euler product identity holds for any category with a zero object, finite coproducts, and "Schur's lemma"
Mar 7, 2023 at 5:01 history edited Zach Goldthorpe CC BY-SA 4.0
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Mar 7, 2023 at 4:57 comment added Zach Goldthorpe @Maiyu Good point, I have made an edit to elaborate on your comment, which at least makes your identity hold true for $\mathbb{Z}\mathbf{Mod}$ (or any abelian category)
Mar 7, 2023 at 4:56 history edited Zach Goldthorpe CC BY-SA 4.0
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Mar 7, 2023 at 4:30 comment added Brian This is great! It sounds like one way to get the definitions to agree, we would start with a semisimple object (from an isomorphism class) and apply the norm to its simple objects instead of the semisimple object itself. However, that’s the geometric series applied to the product and we are distributing term by term, so that doesn’t seem to say anything new.
Mar 7, 2023 at 4:09 history answered Zach Goldthorpe CC BY-SA 4.0