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Mar 4, 2023 at 10:54 comment added Moishe Kohan Right, except van Kampen's theorem gives a somewhat different answer (one needs to add more relators to the amalgams because $\pi_1(\partial B_i)$ does not necessarily embed in the factors). But this does not change the end result.
Mar 4, 2023 at 6:51 comment added Donu Arapura In general, $B_i$ should be a tubular nbhd of a component of the singular set. (I noticed you asked about that previously.) The argument is bit more involved, but should follow the same strategy.
Mar 4, 2023 at 6:32 comment added Higgs-Boson many thank for the answer! I have a question: if the singularties are isolated, then $\tilde{B}_i$ is homotopy equivarlent to $F_i$. But what is the case for general singularities?
Mar 4, 2023 at 3:54 history answered Donu Arapura CC BY-SA 4.0