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Feb 27, 2023 at 19:24 comment added username To complement @MichaelEngelhardt : it isn't possible to compute the eigenvectors of the system when the diagonal is not constant, as it would be is a finite difference approximation of $u^{\prime\prime}(x) +q(x)u(x)=\lambda u(x)$, $u(0)=u(1)=0$, which do not have closed form solutions. In the constant diagonal case, it is explicit.
Feb 27, 2023 at 19:05 comment added Michael Engelhardt I don't see how we can do that without knowing what's on the diagonal ...
Feb 27, 2023 at 18:35 history asked ABB CC BY-SA 4.0