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Oct 30, 2010 at 7:22 comment added Geordie Williamson I don't know of any software. The thing that makes n = 4 much harder than n = 3 is the fact that there are non-trivial (ie \ne 1) KL polynomials. I once worked out the complex for the half twist (but none of its powers) for n = 4 and remember not finding the answer particularly enlightening! If you do manage to get a conceptual picture of what is going on I'd be very interested to hear about it.
Oct 30, 2010 at 2:44 answer added Ben Webster timeline score: 4
Oct 30, 2010 at 1:00 comment added Vivek Shende Thanks Geordie. In fact I spent about the whole day, and not alone either, working out what $\Delta^k$ is for $n=3$, but I guess its description at the end is not all that bad. Do you know what it is for $n=4$? $n=5$? How far does it stay reasonable to write down? Is there any computer software to help me explore this question?
Oct 29, 2010 at 22:31 comment added Geordie Williamson A quick answer is it's complicated ... expressing T_{w_0} in the KL basis involves inverse Kazhdan-Lusztig polynomials, which are again KL polynomials up to (-1)^{?}. Hence the complex corresponding to the half twist will be very complicated for n large enough (but for, eg n = 3 it is easily described). However, I seem to remember Khovanov mentioning that some nice stabilization happens in the Rouquier complex if one takes high powers of the full twist. I am not sure it has ever been written down.
Oct 29, 2010 at 19:52 history edited Vivek Shende CC BY-SA 2.5
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Oct 29, 2010 at 19:51 comment added Vivek Shende well, hopefully the link is improved.
Oct 29, 2010 at 19:46 history edited Vivek Shende CC BY-SA 2.5
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Oct 29, 2010 at 19:19 comment added Jim Humphreys I edited the names, but anyway the link to Wikipedia isn't right.
Oct 29, 2010 at 19:18 history edited Jim Humphreys CC BY-SA 2.5
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Oct 29, 2010 at 17:47 history asked Vivek Shende CC BY-SA 2.5