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Feb 24, 2023 at 23:54 comment added Flavius Aetius This is a very good point! Thank you. What about the orbit type strata $X_H^i$ which are simply the connected components of the isotropy types? We know that they define a canonical stratification of $X$. But are they the canonical stratification in Kaledin's theorem $2.3$?
Feb 24, 2023 at 19:30 history edited LSpice CC BY-SA 4.0
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Feb 24, 2023 at 18:16 comment added Will Sawin You are certainly allowed to take a variety to be a resolution of itself. I don't think $X \to X/G$ is a symplectic resolution because it is not a resolution since it is (usually) not birational.
Feb 24, 2023 at 17:18 comment added Flavius Aetius I made a mistake. I meant to write "symplectic variety", not "symplectic singularity". So, you confirm that $X$ is a symplectic variety, right? It is obvious to me, too. But since there is no symplectic resolution of $X$ other than $X$ itself (if we are allowed to do that), I was wondering if I don't want too much.
Feb 24, 2023 at 17:09 comment added Will Sawin I wouldn't say $X$ is a symplectic singularity but it certainly has symplectic singularities by that definition.
Feb 24, 2023 at 16:55 history asked Flavius Aetius CC BY-SA 4.0