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Feb 24, 2023 at 15:30 comment added Dirk It's more complicated than what you state (just consider $A=-I$ to see that the bounds can not be like you want them in your initial statement).
Feb 24, 2023 at 14:43 comment added Iosif Pinelis Also, looking at your $f(l) \le x \le g(r)$, it seems that you want the lower bound on $x$ to depend only on $l$, and the upper bound on $x$ to depend only on $r$. On the other hand, in your "Concrete example", these "depend only on" conditions do not seem to hold. ??
Feb 24, 2023 at 14:32 comment added Iosif Pinelis In "When can we invert this system?", what do you mean by "when"? Do you want a necessary and sufficient condition? If so, in what terms do you want the condition on $A,l,r$ to be stated?
Feb 24, 2023 at 13:02 comment added Carlo Beenakker but you want not just any linear transformation, but an orthogonal transformation, right? that will not work in general.
Feb 24, 2023 at 12:22 comment added AspiringMat @CarloBeenakker This doesn't rule out that a linear transormation would give such set right? For example, setting $r=m'+z', s=z'+p', t=..$ leading to such set.
Feb 24, 2023 at 11:52 comment added Carlo Beenakker I don't think this is possible: the bounds on $m'$ will depend on $z'$ and $p'$, so you can not hope to obtain an equality of the form $f(m,z,p)\leq m'\leq g(m,z,p)$.
Feb 24, 2023 at 11:28 history asked AspiringMat CC BY-SA 4.0