Timeline for Existence of disintegrations for improper priors on locally-compact groups
Current License: CC BY-SA 4.0
14 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| 15 hours ago | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Aug 20 at 3:03 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Apr 22 at 2:03 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Mar 23 at 1:15 | history | edited | LSpice | CC BY-SA 4.0 |
Name of reference, while this is on the front page
|
| Mar 22 at 22:02 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Nov 23, 2023 at 21:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Jul 26, 2023 at 20:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Mar 28, 2023 at 20:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Feb 26, 2023 at 1:05 | answer | added | Tom LaGatta | timeline score: 1 | |
| Feb 23, 2023 at 6:47 | comment | added | Michael Greinecker | I took a look at the two examples by Chang and Pollard. The problem there seems to be that disintegrations are not unique, not that they do not exist. Also, you may not be able to disintegrate with respect to the marginal. Take the constant function from $\mathbb{R}$, endowed with Lebesgue measure, to $0$. The $\{0\}$-marginal is an infinite point mass and useless for integrating, but you can disintegrate the measure on the product into $\delta_0$ and the kernel that is constant with Lebesgue measure. | |
| Feb 23, 2023 at 6:06 | comment | added | Tom LaGatta | @MichaelGreinecker I like this idea very much but it sounds too good to be true. In Chang & Pollard Examples 11 & 12 are both $\sigma$-finite but admit non-$\sigma$-finite marginals. In your approach, do we need the assumption both that the original measure $\eta$ and its marginal $\kappa_\gamma^\theta$ are $\sigma$-finite, in which case we have this more general disintegration theorem? I'm surprised I haven't found this in the literature, given the wealth of literature on disintegrations of probability measures. P.S. So nice to see you here, hope you are well | |
| Feb 22, 2023 at 8:59 | comment | added | Michael Greinecker | At least for $\sigma$-finite measures, you can take a partition into countably many measurable sets of finite measure, apply the disintegration theorem for each cell, and then combine the resulting disintegrations to one grand disintegration. | |
| Feb 22, 2023 at 5:32 | history | edited | Tom LaGatta | CC BY-SA 4.0 |
added 36 characters in body
|
| Feb 22, 2023 at 5:03 | history | asked | Tom LaGatta | CC BY-SA 4.0 |