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Feb 27, 2023 at 18:30 vote accept M. Winter
Feb 21, 2023 at 13:39 comment added Brendan McKay Yes, that clarifies it, thanks.
Feb 21, 2023 at 11:19 history edited David E Speyer CC BY-SA 4.0
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Feb 21, 2023 at 11:08 history edited David E Speyer CC BY-SA 4.0
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Feb 21, 2023 at 11:07 comment added David E Speyer Wait, the second sentence says " I will give an example of a centrally symmetric polytope in $\mathbb{R}^4$ with $12$ vertices where there is a symmetry of the edge graph interchanging two non-antipodal vertices." This is right; the symmetry interchanges $f(\gamma)$ and $f(\pi-\gamma)$, which are not antipodal, and fixes the others. (I'm going to add "and fixes the other ten vertices" for clarity, though.)
Feb 21, 2023 at 7:35 comment added Brendan McKay You prove that there is a symmetry that doesn't preserve antipodal pairs, which indeed answers the OP. It isn't what your second sentence says though (which is satisfied by my cube example in a comment to Dima's answer that does not answer the OP). I'm only questioning your wording.
Feb 21, 2023 at 3:42 history answered David E Speyer CC BY-SA 4.0