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Feb 20, 2023 at 6:15 history edited მამუკა ჯიბლაძე CC BY-SA 4.0
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Feb 20, 2023 at 6:02 comment added მამუკა ჯიბლაძე @PeterWu Indeed! In my case, $15=\binom62$ and $20=\binom63$, it was stupid not to notice this! Thus combinatorics in general is simply that of 2- and 3-element subsets of $\{1,...,n\}$. Do you know if there is something similar for other simple algebras? I mean, even if not or you don't know, I still think your comment contains a legitimate answer. Maybe somebody else proposes a more complete answer, but so far this one is the only thing we have, right?
Feb 20, 2023 at 1:49 comment added Peter Wu For $so(n)$ this can be done. Say $M_{ij}$ is the generator with $1$ at $i,j$, $-1$ at $j,i$ otherwise $0$. Only $[M_{ij},M_{jk}]=M_{ik}$ and otherwise zero.
Feb 20, 2023 at 0:16 comment added LSpice Do you know if this can be done for $\mathfrak{sl}_3$?
Feb 20, 2023 at 0:07 history edited LSpice CC BY-SA 4.0
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Feb 19, 2023 at 22:15 history asked მამუკა ჯიბლაძე CC BY-SA 4.0