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Feb 17, 2023 at 4:32 comment added Deane Yang I'm pretty sure a pointwise bound of the form $|\nabla s| \le C$, where $C$ depends only on the curvature, is straightforward. But, as you say, $s$ could be oscillating, so a bound such as $|\nabla s| \ge C$, where $C$ depends only on the curvature seems unlikely to me.
Feb 16, 2023 at 18:39 history became hot network question
Feb 16, 2023 at 16:24 comment added Sebastian Goette @DeaneYang Can you explain, please? Do you mean "upper bound on $\nabla s$"? Note that $s$ could be oscillating. Also, do you mean a sign assumption on the curvature of $(M,g)$? I don't see an obvious sign convention for the curvature of $(E,\nabla)$ here.
Feb 16, 2023 at 16:03 comment added Deane Yang An upper bound should be straightforward but a lower bound probably requires a sign assumption on the curvature.
Feb 16, 2023 at 14:56 answer added MyShepherd timeline score: 4
Feb 16, 2023 at 10:32 history asked Sebastian Goette CC BY-SA 4.0