Skip to main content
3 events
when toggle format what by license comment
Feb 16, 2023 at 12:59 comment added Connor But in this recurrence relation, we can't seem to be sure that $f_n(x)$ is all real roots.
Feb 16, 2023 at 12:55 comment added Connor Thanks for your comment! I'm sorry that I forgot to indicate the $n \geq 1$. Based on your comment, then by the generating function of $f_n(x)$, we get the recurrence relation of $f_n(x)$, that is $f_n(x)=xf_{n-1}(x)+x^2f_{n-3}+x^2f_{n-4}$ (for $n \geq 5$).
Feb 16, 2023 at 8:28 history answered Brendan McKay CC BY-SA 4.0