Timeline for Simplified Bing's house
Current License: CC BY-SA 4.0
14 events
when toggle format | what | by | license | comment | |
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Feb 16, 2023 at 9:51 | history | edited | Anton Petrunin | CC BY-SA 4.0 |
added 21 characters in body
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Feb 16, 2023 at 9:33 | vote | accept | Anton Petrunin | ||
Feb 16, 2023 at 9:33 | history | edited | Anton Petrunin | CC BY-SA 4.0 |
deleted 2 characters in body
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Feb 15, 2023 at 21:54 | answer | added | Sam Nead | timeline score: 5 | |
Feb 15, 2023 at 21:53 | comment | added | Sam Nead | I believe that the dunce hat does not have the desired vertex link about its unique “vertex” (point of “order” greater than three). That is, the dunce cap is not a special spine. | |
Feb 15, 2023 at 21:37 | comment | added | Ian Agol | You are probably aware of the dunce hat? | |
Feb 15, 2023 at 20:41 | history | edited | LSpice | CC BY-SA 4.0 |
Name of "this question"
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Feb 15, 2023 at 20:37 | comment | added | Anton Petrunin | @TomGoodwillie Say, maybe 3 vertices are sufficient, or maybe 4 vertices with different design --- that is my question. | |
Feb 15, 2023 at 20:33 | comment | added | Wlod AA | I wonder, is it Bing's? | |
Feb 15, 2023 at 19:54 | history | edited | Anton Petrunin | CC BY-SA 4.0 |
added 51 characters in body
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Feb 15, 2023 at 16:32 | comment | added | Anton Petrunin | @TomGoodwillie well it is simply because all vertices have degree 2, right? | |
Feb 15, 2023 at 12:37 | comment | added | Tom Goodwillie | (This was assuming that none of the curves is a circle, I mean that each of the curves ends at two quadrapod vertices (which might be equal).) | |
Feb 15, 2023 at 12:34 | comment | added | Tom Goodwillie | If Q is the number of quadrapod vertices and T is the number of tripod curves then 2Q=T necessarily, because 6Q-3T will be the Euler characteristic of the boundary of the two-dimensional stratum. | |
Feb 15, 2023 at 12:05 | history | asked | Anton Petrunin | CC BY-SA 4.0 |