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Feb 15, 2023 at 9:14 history became hot network question
Feb 15, 2023 at 8:21 vote accept travis schedler
Feb 15, 2023 at 3:38 comment added mme Thanks for the correction!
Feb 15, 2023 at 3:20 comment added Wlod AA There is a 1-dim simply-connected continuum B that may serve as a counter-example.
Feb 15, 2023 at 2:27 review Close votes
Feb 19, 2023 at 3:07
Feb 15, 2023 at 2:06 answer added Saúl RM timeline score: 9
Feb 15, 2023 at 1:51 comment added M.G. @mme: if I understand the question correctly, it asserts an existence of such an $x$ rather than claiming that it's true for any $x$ on the boundary, i.e. I don't think you are allowed to pick $x=1$ :-)
Feb 15, 2023 at 1:17 comment added mme False. Take B = C (complex plane) and B' = C minus [0,infty) and x = 1.
S Feb 15, 2023 at 1:11 review First questions
Feb 15, 2023 at 3:36
S Feb 15, 2023 at 1:11 history asked travis schedler CC BY-SA 4.0