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Nov 12, 2010 at 19:58 comment added Amit Kumar Gupta Oh sorry, I missed the $\wedge$ in "0, 1, $\wedge$ have the usual meaning." Never mind anything in my previous comment.
Nov 12, 2010 at 10:03 comment added Amit Kumar Gupta How are all elements incomparable? $s_1 \wedge t_1$ and $s_1$ are comparable. In your example, $S \wedge T$ consists of those three joins, and 0, and this set is certainly mutually disjoint.
Oct 29, 2010 at 8:21 history answered Bjørn Kjos-Hanssen CC BY-SA 2.5