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Feb 15, 2023 at 13:29 comment added Dima Pasechnik right - except that the latter cannot be realised by a centrally symmetric polytope - because the centre cannot be at the same time on the top and bottom faces. (basically, one pins down the location of the centre, once there is a quadrangle in the graph preserved by $\phi$.) Hmm, but how to make this kind of argument work in general, I don't know.
Feb 15, 2023 at 8:51 comment added Brendan McKay Consider a cube in its standard orientation. One antipodal structure pairs each vertex with its most distant vertex. Another pairs each vertex on the top face with the vertex diagonally opposite on the top face, and similarly for the bottom face.
Feb 13, 2023 at 23:38 history answered Dima Pasechnik CC BY-SA 4.0