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Aug 28, 2023 at 17:38 history edited LSpice CC BY-SA 4.0
Typo, while this is on the front page
Aug 28, 2023 at 9:27 history edited David Roberts CC BY-SA 4.0
addded links
Oct 30, 2010 at 15:30 comment added Romeo @Andreas, cool, thanks, this kind of thing is perfect (and definitely wouldn't have found that on my own). Never read a paper of Dold before...
Oct 30, 2010 at 15:28 comment added Romeo @Saul: Wow, nice, I've never seen that construction before. Where does it come from?
Oct 29, 2010 at 14:00 comment added Johannes Ebert Or you could take symmetric prodcuts of $S^n$ labelled by elements of any abelian group $A$: that produces $K(A,n)$. But is that "geometric"?
Oct 29, 2010 at 13:13 comment added Saul Glasman More generally, if M is any Moore space (many of these are finite dimensional manifolds!) then taking the geometric realization of the free abelian group on the singular simplices of M will give you the corresponding Eilenberg-MacLane space.
Oct 29, 2010 at 6:22 history edited Andreas Thom CC BY-SA 2.5
added 21 characters in body
Oct 29, 2010 at 6:12 history answered Andreas Thom CC BY-SA 2.5