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Feb 13, 2023 at 9:02 comment added dohmatob Thanks! Indeed, in the Euclidean case $H=\mathbb R^n$, your Lemma 4 answer's my question in the affirmative (by taking $z=0$). The argument though written for the Euclidean case carries over to the Hilbert setting.
Feb 13, 2023 at 2:40 comment added Suvrit plz. check lemma 4 of arxiv.org/pdf/1109.0258.pdf -- a similar proof should help here.
Feb 11, 2023 at 6:52 history edited dohmatob CC BY-SA 4.0
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Feb 11, 2023 at 6:32 history asked dohmatob CC BY-SA 4.0