Timeline for Asymptotic expansion on the following integral of exponential function
Current License: CC BY-SA 4.0
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Feb 13, 2023 at 18:34 | comment | added | Iosif Pinelis | @user497696 : As I said, this would very much depend on the norm. Also, I think in general there will be no such asymptotic at all, because an arbitrary convex function can behave weirdly in any neighborhood of a given point. | |
Feb 13, 2023 at 13:39 | comment | added | user497696 | Thanks for your answer. However, I am wondering if it is possible to derive a result that $I(M) = V(M) (1 + o(1))$, where $V(M)$ is a certain analytical function? In other words, the small $o(\cdot)$ notation should lie outside the exponent term. | |
Feb 9, 2023 at 14:56 | history | answered | Iosif Pinelis | CC BY-SA 4.0 |