Timeline for Equivariant spectrum with coefficients
Current License: CC BY-SA 4.0
5 events
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Feb 8, 2023 at 12:57 | comment | added | Neil Strickland | This was asked at mathoverflow.net/questions/431226/… and answered in the comments. The category of $G$-equivariant spectra (like any stable $\infty$-category) is enriched over the category of spectra, so you can just define $EA=E\wedge M(A)$ again. | |
Feb 7, 2023 at 18:03 | comment | added | anon | No, I want to see whether the generalisation of spectrum with coefficients is possible in the equivariant case. I am curious whether there is such a thing as an equivariant spectrum with coefficients. | |
Feb 7, 2023 at 17:43 | comment | added | user43326 | Do you want $G$ go act on $A$? In that case there are obstructions, cf. jstor.org/stable/2154066 | |
S Feb 7, 2023 at 13:39 | review | First questions | |||
Feb 7, 2023 at 13:44 | |||||
S Feb 7, 2023 at 13:39 | history | asked | anon | CC BY-SA 4.0 |