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Dec 17, 2023 at 14:49 history edited David White CC BY-SA 4.0
Fixed minor typo, grammar.
Dec 17, 2023 at 14:21 vote accept Arshak Aivazian
Dec 17, 2023 at 12:45 answer added David White timeline score: 3
Feb 7, 2023 at 18:57 comment added Arshak Aivazian @ZhenLin Of course, I mean the adjunction between $T[M]$ and $M^S$, where $T$ is an algebraic theory with a set of sorts $S$. The forgetting functor returns a tuple of all carriers. I really hoped that adjunction and monadicity were the same here, thanks, glad to hear that!
Feb 6, 2023 at 22:59 comment added Zhen Lin The obstruction to monadicity is, almost always in practice, the existence of the left adjoint. Aside from that it is not hard to ensure that the conditions of the strict monadicity theorem are satisfied: so, indeed, the category of algebras of a single sorted Lawvere theory in abelian category will be monadic over the abelian category iff the left adjoint exists. The issue with multi sorted Lawvere theories is that there is no canonical candidate for a forgetful functor, so your question does not quite make sense in that context.
Feb 6, 2023 at 19:44 comment added Arshak Aivazian Although the Cartesian-closure condition is somewhat restrictive, since excludes Abelian categories. Does the category of chain complexes in a good abelian category satisfy the condition under discussion?
Feb 6, 2023 at 18:43 comment added Arshak Aivazian Thank you very much, this is very helpful! Then "bicomplete cartesian-closed category" is my answer to the first question (because it is natural sufficient condition for being a monoidally cocomplete category as defined by Todd Trimble).
Feb 6, 2023 at 18:26 comment added varkor For your first question, see this discussion by Todd Trimble.
Feb 6, 2023 at 17:46 history edited Arshak Aivazian CC BY-SA 4.0
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Feb 6, 2023 at 17:39 history edited Arshak Aivazian CC BY-SA 4.0
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Feb 6, 2023 at 17:22 history asked Arshak Aivazian CC BY-SA 4.0