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Feb 5, 2023 at 17:51 comment added dohmatob I've corrected the bugs in the statement of the question and posted a complete solution in an edit. The bugs where due to the fact that what I defined as $\omega$ was meant to be the dual norm of $\omega$ (i.e the support function of its unit ball). Thanks for the input
Feb 5, 2023 at 17:47 history edited dohmatob CC BY-SA 4.0
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Feb 5, 2023 at 17:41 history edited dohmatob CC BY-SA 4.0
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Feb 5, 2023 at 17:32 comment added Iosif Pinelis Yes, the proof is very simple.
Feb 5, 2023 at 17:30 comment added dohmatob Hum, yes I think I see how to get the proof, by simply observing that $1/\min(a,b) = \max(1/a,1/b) \le 1/a + 1/b$. This would give the $\sqrt 2$ factor.
Feb 5, 2023 at 17:22 comment added Iosif Pinelis Also, your desired conclusion seems to be just stated, without proof, in the paper linked in your comment -- even though the proof is simple.
Feb 5, 2023 at 17:15 comment added dohmatob Indeed, there are a couple of typographical mistakes. Editing. Thanks.
Feb 5, 2023 at 17:12 comment added Iosif Pinelis Two more mistakes remaining there (try replacing $\lambda_j$ and $r^2$ by $t^2\lambda_j$ and $t^2r^2$).
Feb 5, 2023 at 17:12 comment added dohmatob Concerning your, other comments, it is indeed shown in the reference that $D(r) \subseteq \mathcal E(r) \subseteq \sqrt{2} D(r)$, where $D(r) := \{x \in \mathbb R^d \mid \sum_j x_j^2/\lambda_j(r) \le 1\}$. There is no randomness involved here. The claim then follows upon comparing the support functions of these sets . No ?
Feb 5, 2023 at 17:09 comment added dohmatob I omitted a square root sign in the definition of $\omega$. Fixed.
Feb 5, 2023 at 17:07 history edited dohmatob CC BY-SA 4.0
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Feb 5, 2023 at 17:03 comment added Iosif Pinelis (i) Your inequality cannot be true, as it is not homogeneous in $x$. There seem to be three mistakes in the definition of $\omega$. (ii) Theorem 2.1 in the paper linked in your comment seems rather different from whatever you wanted to ask here. In particular, it involves random variables, in contrast with your post.
Feb 5, 2023 at 16:51 comment added dohmatob Sorry for the noise, but it turns our the problem is solved by an argument of Theorem 2.1 of this paper jmlr.org/papers/volume4/mendelson03a/mendelson03a.pdf. I'll close the question if nobody objects to it.
Feb 5, 2023 at 16:42 history edited dohmatob CC BY-SA 4.0
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Feb 5, 2023 at 16:31 history asked dohmatob CC BY-SA 4.0