Timeline for Does the Cheeger constant satisfy a heat-type equation?
Current License: CC BY-SA 4.0
10 events
when toggle format | what | by | license | comment | |
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Nov 10 at 9:47 | comment | added | Enhao Lan | Thanks very much. Don't be hurry, my time is enough. | |
Nov 9 at 16:41 | comment | added | Hollis Williams | Thanks for your observations, I am slightly busy at the moment with other things but I will think about this and get back to you. | |
Nov 8 at 9:32 | comment | added | Enhao Lan | Besides, I'm pretty sure the Cheeger constant (which is defined by (3)) is non-decreasing under the Ricci flow on 2-sphere without your restricted condition. However, about this, the method in [4] (An isoperimetric estimate for the Ricci flow on the two-sphere) does not work. | |
Nov 8 at 9:31 | comment | added | Enhao Lan | Your mailbox rejected my email. But my question is very simple. In your new paper (arxiv.org/pdf/2404.13063), I don't see the equivalence between (3) and (4). Although they differ only twice on the round sphere, there seems to be no definite proportional relationship between them on the ordinary topological sphere. | |
Oct 21 at 23:43 | comment | added | Hollis Williams | @EnhaoLan Great, I look forward to this discussion. | |
Oct 21 at 11:48 | comment | added | Enhao Lan | Thank you. I read your paper last year. There are a few details I don't understand. I'll send you an email in three weeks, because I have some unfinished business, and I also need some time to recall your paper. Thanks again. | |
Oct 20 at 14:48 | comment | added | Hollis Williams | @EnhaoLan Hi Enhao, did you maybe want to send me an email as might be easier to explain there. | |
Feb 15, 2023 at 12:06 | comment | added | Enhao Lan | About one year ago, I feel the $h(M)$ maybe monotone along Ricci flow before singularity. But I don't know how to prove it, even though on special manifold. Since I just be a beginner of Ricci flow, I give up it. But I still be interested in it. If possible, could you tell me the calculation about (1). Thanks very much. | |
Feb 5, 2023 at 15:53 | vote | accept | Hollis Williams | ||
Feb 5, 2023 at 15:53 | history | answered | Hollis Williams | CC BY-SA 4.0 |