Timeline for An inequality involving the essential supremum
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 4, 2023 at 22:15 | vote | accept | Nate River | ||
| Feb 4, 2023 at 22:15 | comment | added | Nate River | Ah yes, I just thought of that as well. You don’t have to union over all $x \in A$. Nice. | |
| Feb 4, 2023 at 22:15 | comment | added | Fedor Petrov | Let $\alpha=\sup A$. If $\alpha\in A$, then $A=A\cap [0,\alpha]$, otherwise $A=\cup (A\cap [0,\alpha_n])$, where $\alpha_n\in A$ approach $\alpha$ | |
| Feb 4, 2023 at 22:13 | comment | added | Nate River | Hm, wait actually, how do you get the countable union? Since the set of $x \in A$ may be uncountable, you may have to take an uncountable union of sets of the form $A \cap [0, x]$. Am I missing something? | |
| Feb 4, 2023 at 22:03 | vote | accept | Nate River | ||
| Feb 4, 2023 at 22:12 | |||||
| Feb 4, 2023 at 22:03 | comment | added | Nate River | Very slick, nice! | |
| Feb 4, 2023 at 21:37 | history | answered | Fedor Petrov | CC BY-SA 4.0 |