Skip to main content
added 6 characters in body
Source Link
Robert Israel
  • 54.2k
  • 1
  • 76
  • 152

It is not unique. Maple solves your differential equation in terms of HeunC functions:

$$w \! \left(t \right) = c_{1} \mathit{HeunC} \left(2 n -1, n -1, n -2, -n^{2}+\frac{1}{2}, \frac{n^{2}}{2}+\frac{1}{2}, t\right)+c_{2} t^{-n +1} \mathit{HeunC} \left(2 n -1, -n +1, n -2, -n^{2}+\frac{1}{2}, \frac{n^{2}}{2}+\frac{1}{2}, t\right)$$ The first basic solution $$ \mathit{HeunC} \left(2 n -1, n -1, n -2, -n^{2}+\frac{1}{2}, \frac{n^{2}}{2}+\frac{1}{2}, t\right)$$ is analytic in the open unit disk.

It is not unique. Maple solves your differential equation in terms of HeunC functions:

$$w \! \left(t \right) = c_{1} \mathit{HeunC} \left(2 n -1, n -1, n -2, -n^{2}+\frac{1}{2}, \frac{n^{2}}{2}+\frac{1}{2}, t\right)+c_{2} t^{-n +1} \mathit{HeunC} \left(2 n -1, -n +1, n -2, -n^{2}+\frac{1}{2}, \frac{n^{2}}{2}+\frac{1}{2}, t\right)$$ The first solution $$ \mathit{HeunC} \left(2 n -1, n -1, n -2, -n^{2}+\frac{1}{2}, \frac{n^{2}}{2}+\frac{1}{2}, t\right)$$ is analytic in the open unit disk.

It is not unique. Maple solves your differential equation in terms of HeunC functions:

$$w \! \left(t \right) = c_{1} \mathit{HeunC} \left(2 n -1, n -1, n -2, -n^{2}+\frac{1}{2}, \frac{n^{2}}{2}+\frac{1}{2}, t\right)+c_{2} t^{-n +1} \mathit{HeunC} \left(2 n -1, -n +1, n -2, -n^{2}+\frac{1}{2}, \frac{n^{2}}{2}+\frac{1}{2}, t\right)$$ The first basic solution $$ \mathit{HeunC} \left(2 n -1, n -1, n -2, -n^{2}+\frac{1}{2}, \frac{n^{2}}{2}+\frac{1}{2}, t\right)$$ is analytic in the open unit disk.

Source Link
Robert Israel
  • 54.2k
  • 1
  • 76
  • 152

It is not unique. Maple solves your differential equation in terms of HeunC functions:

$$w \! \left(t \right) = c_{1} \mathit{HeunC} \left(2 n -1, n -1, n -2, -n^{2}+\frac{1}{2}, \frac{n^{2}}{2}+\frac{1}{2}, t\right)+c_{2} t^{-n +1} \mathit{HeunC} \left(2 n -1, -n +1, n -2, -n^{2}+\frac{1}{2}, \frac{n^{2}}{2}+\frac{1}{2}, t\right)$$ The first solution $$ \mathit{HeunC} \left(2 n -1, n -1, n -2, -n^{2}+\frac{1}{2}, \frac{n^{2}}{2}+\frac{1}{2}, t\right)$$ is analytic in the open unit disk.