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Oct 24, 2012 at 8:15 answer added Markus Schweighofer timeline score: 3
Oct 29, 2010 at 8:43 comment added Boris Bukh Is it NP-hard in fixed dimension, though?
Oct 28, 2010 at 22:13 comment added alex NP-hardness is one barrier for this kind of theorem, since it is NP-hard to check if a multi-variable polynomial has at least one root. It is still NP-hard if you restrict yourself to polynomials which have finitely many roots all of which must be in $[0,1]^n$. So any counting algorithm would take at least exponential time in $n$.
Oct 28, 2010 at 19:30 vote accept Boris Bukh
Oct 28, 2010 at 15:30 answer added Thierry Zell timeline score: 9
Oct 28, 2010 at 15:17 answer added David E Speyer timeline score: 10
Oct 28, 2010 at 14:37 history asked Boris Bukh CC BY-SA 2.5