Timeline for Commuting real elements in finite groups
Current License: CC BY-SA 4.0
15 events
| when toggle format | what | by | license | comment | |
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| Jan 31, 2023 at 11:45 | comment | added | Nick | My apologies. I meant $x'$ and $y$ do not necessarily commute. $x'$ is just some random element of order $p$, not every element of order $p$. | |
| Jan 31, 2023 at 7:07 | comment | added | მამუკა ჯიბლაძე | In the first version, $x'yz$ has order $pqr$, right? | |
| Jan 31, 2023 at 6:33 | history | edited | Martin Sleziak |
added a top-level tag; see: https://meta.mathoverflow.net/questions/1457/why-are-mo-tags-formatted-as-they-are
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| Jan 30, 2023 at 19:03 | history | edited | Nick | CC BY-SA 4.0 |
more relevant title
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| Jan 30, 2023 at 16:38 | history | edited | Nick | CC BY-SA 4.0 |
Added background
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| Jan 30, 2023 at 16:32 | comment | added | Nick | Thanks for pointing out. I added back the assumption that $|G|$ is divisible by $p,q,r$ to the first power only. | |
| Jan 30, 2023 at 16:31 | history | edited | Nick | CC BY-SA 4.0 |
added 60 characters in body
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| Jan 30, 2023 at 16:28 | comment | added | Achim Krause | (in the first version you restrict the primes to be odd, but $\Sigma_{12}$ with $3,5,7$ works just as well.) | |
| Jan 30, 2023 at 16:22 | comment | added | Achim Krause | For the rephrased version (which dropped the condition that $p, q, r$ divide $|G|$ to the first power only), I think $G=\Sigma_8$ with $p, q, r$ given by $2, 3,5$ is a counterexample. | |
| Jan 30, 2023 at 15:33 | history | edited | LSpice | CC BY-SA 4.0 |
does $G$ must -> must $G$
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| Jan 30, 2023 at 15:27 | history | edited | Nick | CC BY-SA 4.0 |
Restating the question in a more clear fashion
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| Jan 30, 2023 at 15:24 | history | edited | YCor | CC BY-SA 4.0 |
removed capitals from title
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| Jan 30, 2023 at 15:16 | comment | added | LSpice | Could you say something about how this condition arises, and why you suspect it might have this consequence? \\ $x$ and $x'$ are unrelated, except that they happen to have the same order? If so, then you might want to change the title slightly, or at least change the notation from $x'$ to something else; "commuting prime order elements" makes it easy to misread the question, though it is precisely stated. | |
| Jan 30, 2023 at 14:52 | history | edited | Nick | CC BY-SA 4.0 |
added 7 characters in body
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| Jan 30, 2023 at 13:04 | history | asked | Nick | CC BY-SA 4.0 |