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Jan 24, 2023 at 17:42 history edited shahulhameed CC BY-SA 4.0
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Jan 24, 2023 at 17:39 comment added shahulhameed My guess for the upper bound came by taking the example $x_1=2(n-1)$, $,x_2=x_3=\cdots=x_n=n-2$ and $k_1=k_2=k_3=\cdots=k_{n-1}=n$ and $k_n=0$. So that sum of x values and i values each equal to $n(n-1)$
Jan 24, 2023 at 17:27 history edited shahulhameed CC BY-SA 4.0
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Jan 24, 2023 at 9:41 history edited YCor CC BY-SA 4.0
formatting, added tag
Jan 24, 2023 at 9:39 history asked shahulhameed CC BY-SA 4.0