Timeline for Identity involving Stirling number of the second kind
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 20, 2023 at 10:24 | vote | accept | Tim Seppelt | ||
| Jan 19, 2023 at 19:15 | comment | added | მამუკა ჯიბლაძე | Sorry for confusion, indeed this is a different identity! | |
| Jan 19, 2023 at 19:00 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Jan 19, 2023 at 18:59 | comment | added | Iosif Pinelis | @მამუკაჯიბლაძე : Thank you for your comment. Then you will probably need some other identity as well, because on the right-hand side you will have $\sum_{m=1}^n S(n,m)(-1)^m m!$ rather than $\sum_{m=1}^n S(n,m)(-1)^m(m-1)!$ (also $(-1)^n$ instead of $0$ on the left). | |
| Jan 19, 2023 at 18:49 | comment | added | მამუკა ჯიბლაძე | You can also substitute $x=-1$ | |
| Jan 19, 2023 at 18:28 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Jan 19, 2023 at 18:17 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Jan 19, 2023 at 17:46 | history | answered | Iosif Pinelis | CC BY-SA 4.0 |