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Jan 24 at 12:06 comment added Claude Leibovici Did you look at Kummer-type transformations ?
Jan 20, 2023 at 19:36 answer added Alexandru Ionut timeline score: 0
Jan 20, 2023 at 19:02 answer added Aaron Hendrickson timeline score: 1
Jan 20, 2023 at 7:54 comment added lrnv @RobertIsrael Thanks, wolfram reduced this for integers a too, but I am interested in general a. @AaronHendrickson, Yes, I am looking for a good way to evaluate it correctly !
Jan 19, 2023 at 22:30 answer added Fred Hucht timeline score: 2
Jan 19, 2023 at 20:24 comment added Aaron Hendrickson Are you just looking for ways to numerically evaluate this hypergeometric function?
Jan 19, 2023 at 18:09 comment added Robert Israel And for $a=2$, $$ 4 \frac{e^z - \text{Ei}(z) +\gamma-1+\ln(z)}{z^2} $$
Jan 19, 2023 at 17:52 comment added Robert Israel If $a$ is a positive integer, it seems you can express it in terms of exponential integral or incomplete Gamma functions. Thus for $a=1$, it is $$\frac{\,\mathrm{Ei}\! \left(z \right)- \gamma -\ln \! \left(z \right)}{ z}$$
Jan 19, 2023 at 17:15 comment added Gerald Edgar This series satisfies the differential equation $$F \left( z \right) {a}^{2}+ \left( 2\,a+1 \right)z {\frac {\rm d}{ {\rm d}z}}F \left( z \right) +{z}^{2}{\frac {{\rm d}^{2}}{{\rm d}{z}^{ 2}}}F \left( z \right) ={a}^{2}{{\rm e}^{z}}$$But when I ask Maple to solve this DE, I get something involving that ${}_2F_2$.
Jan 19, 2023 at 16:56 comment added Carlo Beenakker it does not reduce to any elementary function.
Jan 19, 2023 at 16:29 history asked lrnv CC BY-SA 4.0