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Tom Goodwillie
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I think that this works.

EDIT: No, it doesn't. See John Rognes's comment.

Notation: For a point $x\in EG$ we may symbolically write $x=\sum_{j=0}^nt_jg_j$, where $g_0,\dots ,g_n$ is an ordered tuple of distinct elements of $G$ and $t_j\ge 0$ and $\sum_jt_j=1$. Here the face relations are accounted for by agreeing that if $t_j=0$ for some $j$ then $g_j$ can be omitted from the tuple and the term $t_jg_j$ can be omitted from the expression, without changing the point $x$.

Invariant open cover of $EG$: For $p\ge 0$ let $U_p\subset EG$ consist of the points $x=\sum_{j=0}^nt_jg_j$ such that there is a (necessarily unique) subset $S(x)\subset \{0,n\}$ of cardinality $p+1$ such that

(1) $t_j>t_k$ whenever $j\in S(x)$ and $k\notin S(x)$, and

(2) $t_j>0$ whenever $j\in S(x)$.

Thus for each $n$-simplex $\sigma=[g_0,\dots ,g_n]$ the set $U_p\cap\sigma$ is as follows. If $p\le n$ then it is the disjoint union of convex open subsets, one for each $p$-dimensional face $\tau\subset\sigma$, namely the open star, in the barycentric subdivision of $\sigma$, of the barycenter of $\tau$. It is empty if $p>n$.

This is well-defined (compatible with the face relations), and open. The union of the sets $U_p$ is all of $EG$. For each $p$ the set $U_p$ is invariant under the action of $G$.

Local trivializations: Now let's show that the bundle is trivial over the image of $U_p$, by describing a cross-section. Let $V_p\subset U_p$ consist of those points $x=\sum_jt_jg_j\in U_p$ such that when $j_0$ is the smallest element of the set $S(x)$ then $g_j=e$. This is open in $U_p$, and every point in $U_p$ is uniquely expressible as $gx$ for some $g\in G$ and $x\in V_p$.I think

I think that this works.

Notation: For a point $x\in EG$ we may symbolically write $x=\sum_{j=0}^nt_jg_j$, where $g_0,\dots ,g_n$ is an ordered tuple of distinct elements of $G$ and $t_j\ge 0$ and $\sum_jt_j=1$. Here the face relations are accounted for by agreeing that if $t_j=0$ for some $j$ then $g_j$ can be omitted from the tuple and the term $t_jg_j$ can be omitted from the expression, without changing the point $x$.

Invariant open cover of $EG$: For $p\ge 0$ let $U_p\subset EG$ consist of the points $x=\sum_{j=0}^nt_jg_j$ such that there is a (necessarily unique) subset $S(x)\subset \{0,n\}$ of cardinality $p+1$ such that

(1) $t_j>t_k$ whenever $j\in S(x)$ and $k\notin S(x)$, and

(2) $t_j>0$ whenever $j\in S(x)$.

Thus for each $n$-simplex $\sigma=[g_0,\dots ,g_n]$ the set $U_p\cap\sigma$ is as follows. If $p\le n$ then it is the disjoint union of convex open subsets, one for each $p$-dimensional face $\tau\subset\sigma$, namely the open star, in the barycentric subdivision of $\sigma$, of the barycenter of $\tau$. It is empty if $p>n$.

This is well-defined (compatible with the face relations), and open. The union of the sets $U_p$ is all of $EG$. For each $p$ the set $U_p$ is invariant under the action of $G$.

Local trivializations: Now let's show that the bundle is trivial over the image of $U_p$, by describing a cross-section. Let $V_p\subset U_p$ consist of those points $x=\sum_jt_jg_j\in U_p$ such that when $j_0$ is the smallest element of the set $S(x)$ then $g_j=e$. This is open in $U_p$, and every point in $U_p$ is uniquely expressible as $gx$ for some $g\in G$ and $x\in V_p$.I think

I think that this works.

EDIT: No, it doesn't. See John Rognes's comment.

Notation: For a point $x\in EG$ we may symbolically write $x=\sum_{j=0}^nt_jg_j$, where $g_0,\dots ,g_n$ is an ordered tuple of distinct elements of $G$ and $t_j\ge 0$ and $\sum_jt_j=1$. Here the face relations are accounted for by agreeing that if $t_j=0$ for some $j$ then $g_j$ can be omitted from the tuple and the term $t_jg_j$ can be omitted from the expression, without changing the point $x$.

Invariant open cover of $EG$: For $p\ge 0$ let $U_p\subset EG$ consist of the points $x=\sum_{j=0}^nt_jg_j$ such that there is a (necessarily unique) subset $S(x)\subset \{0,n\}$ of cardinality $p+1$ such that

(1) $t_j>t_k$ whenever $j\in S(x)$ and $k\notin S(x)$, and

(2) $t_j>0$ whenever $j\in S(x)$.

Thus for each $n$-simplex $\sigma=[g_0,\dots ,g_n]$ the set $U_p\cap\sigma$ is as follows. If $p\le n$ then it is the disjoint union of convex open subsets, one for each $p$-dimensional face $\tau\subset\sigma$, namely the open star, in the barycentric subdivision of $\sigma$, of the barycenter of $\tau$. It is empty if $p>n$.

This is well-defined (compatible with the face relations), and open. The union of the sets $U_p$ is all of $EG$. For each $p$ the set $U_p$ is invariant under the action of $G$.

Local trivializations: Now let's show that the bundle is trivial over the image of $U_p$, by describing a cross-section. Let $V_p\subset U_p$ consist of those points $x=\sum_jt_jg_j\in U_p$ such that when $j_0$ is the smallest element of the set $S(x)$ then $g_j=e$. This is open in $U_p$, and every point in $U_p$ is uniquely expressible as $gx$ for some $g\in G$ and $x\in V_p$.I think

added 90 characters in body
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Tom Goodwillie
  • 55.9k
  • 7
  • 151
  • 240

I think that this works.

Notation: For a point $x\in EG$ we may symbolically write $x=\sum_{j=0}^nt_jg_j$, where $g_0,\dots ,g_n$ is an ordered tuple of distinct elements of $G$ and $t_j\ge 0$ and $\sum_jt_j=1$. Here the face relations are accounted for by agreeing that if $t_j=0$ for some $j$ then $g_j$ can be omitted from the tuple and the term $t_jg_j$ can be omitted from the expression, without changing the point $x$.

Invariant open cover of $EG$: For $p\ge 0$ let $U_p\subset EG$ consist of the points $x=\sum_{j=0}^nt_jg_j$ such that there is a (necessarily unique) subset $S(x)\subset \{0,n\}$ of cardinality $p+1$ such that

(1) $t_j>t_k$ whenever $j\in S(x)$ and $k\notin S(x)$, and

(2) $t_j>0$ whenever $j\in S(x)$.

To say it another way:Thus for each simplex $n$-simplex $\sigma=[g_0,\dots ,g_n]$ the set $U_p\cap\sigma$ is as follows. If $p\le n$ then it is the disjoint union of theconvex open stars of thesubsets, one for each $p$-dimensional faces of $\sigma$ ifface $p< n$$\tau\subset\sigma$, it isnamely the interioropen star, in the barycentric subdivision of $\sigma$ if $p=n$, and itof the barycenter of $\tau$. It is empty if $p>n$.

This is well-defined (compatible with the face relations), and open. The union of the sets $U_p$ is all of $EG$. For each $p$ the set $U_p$ is invariant under the action of $G$.

Local trivializations: Now let's show that the bundle is trivial over the image of $U_p$, by describing a cross-section. Let $V_p\subset U_p$ consist of those points $x=\sum_jt_jg_j\in U_p$ such that when $j_0$ is the smallest element of the set $S(x)$ then $g_j=e$. This is open in $U_p$, and every point in $U_p$ is uniquely expressible as $gx$ for some $g\in G$ and $x\in V_p$.I think

I think that this works.

Notation: For a point $x\in EG$ we may symbolically write $x=\sum_{j=0}^nt_jg_j$, where $g_0,\dots ,g_n$ is an ordered tuple of distinct elements of $G$ and $t_j\ge 0$ and $\sum_jt_j=1$. Here the face relations are accounted for by agreeing that if $t_j=0$ for some $j$ then $g_j$ can be omitted from the tuple and the term $t_jg_j$ can be omitted from the expression, without changing the point $x$.

Invariant open cover of $EG$: For $p\ge 0$ let $U_p\subset EG$ consist of the points $x=\sum_{j=0}^nt_jg_j$ such that there is a (necessarily unique) subset $S(x)\subset \{0,n\}$ of cardinality $p+1$ such that

(1) $t_j>t_k$ whenever $j\in S(x)$ and $k\notin S(x)$, and

(2) $t_j>0$ whenever $j\in S(x)$.

To say it another way: for each simplex $\sigma=[g_0,\dots ,g_n]$ the set $U_p\cap\sigma$ is the union of the open stars of the $p$-dimensional faces of $\sigma$ if $p< n$, it is the interior of $\sigma$ if $p=n$, and it is empty if $p>n$.

This is well-defined (compatible with the face relations), and open. The union of the sets $U_p$ is all of $EG$. For each $p$ the set $U_p$ is invariant under the action of $G$.

Local trivializations: Now let's show that the bundle is trivial over the image of $U_p$, by describing a cross-section. Let $V_p\subset U_p$ consist of those points $x=\sum_jt_jg_j\in U_p$ such that when $j_0$ is the smallest element of the set $S(x)$ then $g_j=e$. This is open in $U_p$, and every point in $U_p$ is uniquely expressible as $gx$ for some $g\in G$ and $x\in V_p$.I think

I think that this works.

Notation: For a point $x\in EG$ we may symbolically write $x=\sum_{j=0}^nt_jg_j$, where $g_0,\dots ,g_n$ is an ordered tuple of distinct elements of $G$ and $t_j\ge 0$ and $\sum_jt_j=1$. Here the face relations are accounted for by agreeing that if $t_j=0$ for some $j$ then $g_j$ can be omitted from the tuple and the term $t_jg_j$ can be omitted from the expression, without changing the point $x$.

Invariant open cover of $EG$: For $p\ge 0$ let $U_p\subset EG$ consist of the points $x=\sum_{j=0}^nt_jg_j$ such that there is a (necessarily unique) subset $S(x)\subset \{0,n\}$ of cardinality $p+1$ such that

(1) $t_j>t_k$ whenever $j\in S(x)$ and $k\notin S(x)$, and

(2) $t_j>0$ whenever $j\in S(x)$.

Thus for each $n$-simplex $\sigma=[g_0,\dots ,g_n]$ the set $U_p\cap\sigma$ is as follows. If $p\le n$ then it is the disjoint union of convex open subsets, one for each $p$-dimensional face $\tau\subset\sigma$, namely the open star, in the barycentric subdivision of $\sigma$, of the barycenter of $\tau$. It is empty if $p>n$.

This is well-defined (compatible with the face relations), and open. The union of the sets $U_p$ is all of $EG$. For each $p$ the set $U_p$ is invariant under the action of $G$.

Local trivializations: Now let's show that the bundle is trivial over the image of $U_p$, by describing a cross-section. Let $V_p\subset U_p$ consist of those points $x=\sum_jt_jg_j\in U_p$ such that when $j_0$ is the smallest element of the set $S(x)$ then $g_j=e$. This is open in $U_p$, and every point in $U_p$ is uniquely expressible as $gx$ for some $g\in G$ and $x\in V_p$.I think

added 248 characters in body
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Tom Goodwillie
  • 55.9k
  • 7
  • 151
  • 240

I think that this works.

Notation: For a point $x\in EG$ we may symbolically write $x=\sum_{j=0}^nt_jg_j$, where $g_0,\dots ,g_n$ is an ordered tuple of distinct elements of $G$ and $t_j\ge 0$ and $\sum_jt_j=1$. Here the face relations are accounted for by agreeing that if $t_j=0$ for some $j$ then $g_j$ can be omitted from the tuple and the term $t_jg_j$ can be omitted from the expression, without changing the point $x$.

Invariant open cover of $EG$: For $p>0$$p\ge 0$ let $U_p\subset EG$ consist of the points $x=\sum_{j=0}^nt_jg_j$ such that there is a (necessarily unique) subset $S(x)\subset \{0,n\}$ of cardinality $p$$p+1$ such that

(1) $t_j>t_k$ whenever $j\in S(x)$ and $k\notin S(x)$, and

(2) $t_j>0$ whenever $j\in S(x)$.

To say it another way: for each simplex $\sigma=[g_0,\dots ,g_n]$ the set $U_p\cap\sigma$ is the union of the open stars of the $p$-dimensional faces of $\sigma$ if $p< n$, it is the interior of $\sigma$ if $p=n$, and it is empty if $p>n$.

This is well-defined (compatible with the face relations), and open. The union of the sets $U_p$ is all of $EG$. For each $p$ the set $U_p$ is invariant under the action of $G$.

Local trivializations: Now let's show that the bundle is trivial over the image of $U_p$, by describing a cross-section. Let $V_p\subset U_p$ consist of those points $x=\sum_jt_jg_j\in U_p$ such that when $j_0$ is the smallest element of the set $S(x)$ then $g_j=e$. This is open in $U_p$, and every point in $U_p$ is uniquely expressible as $gx$ for some $g\in G$ and $x\in V_p$.I think

I think that this works.

Notation: For a point $x\in EG$ we may symbolically write $x=\sum_{j=0}^nt_jg_j$, where $g_0,\dots ,g_n$ is an ordered tuple of distinct elements of $G$ and $t_j\ge 0$ and $\sum_jt_j=1$. Here the face relations are accounted for by agreeing that if $t_j=0$ for some $j$ then $g_j$ can be omitted from the tuple and the term $t_jg_j$ can be omitted from the expression, without changing the point $x$.

Invariant open cover of $EG$: For $p>0$ let $U_p\subset EG$ consist of the points $x=\sum_{j=0}^nt_jg_j$ such that there is a (necessarily unique) subset $S(x)\subset \{0,n\}$ of cardinality $p$ such that

(1) $t_j>t_k$ whenever $j\in S(x)$ and $k\notin S(x)$, and

(2) $t_j>0$ whenever $j\in S(x)$.

This is well-defined (compatible with the face relations), and open. The union of the sets $U_p$ is all of $EG$. For each $p$ the set $U_p$ is invariant under the action of $G$.

Local trivializations: Now let's show that the bundle is trivial over the image of $U_p$, by describing a cross-section. Let $V_p\subset U_p$ consist of those points $x=\sum_jt_jg_j\in U_p$ such that when $j_0$ is the smallest element of the set $S(x)$ then $g_j=e$. This is open in $U_p$, and every point in $U_p$ is uniquely expressible as $gx$ for some $g\in G$ and $x\in V_p$.I think

I think that this works.

Notation: For a point $x\in EG$ we may symbolically write $x=\sum_{j=0}^nt_jg_j$, where $g_0,\dots ,g_n$ is an ordered tuple of distinct elements of $G$ and $t_j\ge 0$ and $\sum_jt_j=1$. Here the face relations are accounted for by agreeing that if $t_j=0$ for some $j$ then $g_j$ can be omitted from the tuple and the term $t_jg_j$ can be omitted from the expression, without changing the point $x$.

Invariant open cover of $EG$: For $p\ge 0$ let $U_p\subset EG$ consist of the points $x=\sum_{j=0}^nt_jg_j$ such that there is a (necessarily unique) subset $S(x)\subset \{0,n\}$ of cardinality $p+1$ such that

(1) $t_j>t_k$ whenever $j\in S(x)$ and $k\notin S(x)$, and

(2) $t_j>0$ whenever $j\in S(x)$.

To say it another way: for each simplex $\sigma=[g_0,\dots ,g_n]$ the set $U_p\cap\sigma$ is the union of the open stars of the $p$-dimensional faces of $\sigma$ if $p< n$, it is the interior of $\sigma$ if $p=n$, and it is empty if $p>n$.

This is well-defined (compatible with the face relations), and open. The union of the sets $U_p$ is all of $EG$. For each $p$ the set $U_p$ is invariant under the action of $G$.

Local trivializations: Now let's show that the bundle is trivial over the image of $U_p$, by describing a cross-section. Let $V_p\subset U_p$ consist of those points $x=\sum_jt_jg_j\in U_p$ such that when $j_0$ is the smallest element of the set $S(x)$ then $g_j=e$. This is open in $U_p$, and every point in $U_p$ is uniquely expressible as $gx$ for some $g\in G$ and $x\in V_p$.I think

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Tom Goodwillie
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