Timeline for Non-dominant polynomial maps in the plane
Current License: CC BY-SA 2.5
5 events
| when toggle format | what | by | license | comment | |
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| Oct 27, 2010 at 22:30 | comment | added | Terry Tao | OK, I've reworded the answer to only claim the characteristic zero case, then, rather than the perfect case. | |
| Oct 27, 2010 at 22:30 | history | edited | Terry Tao | CC BY-SA 2.5 |
added 4 characters in body; added 8 characters in body
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| Oct 27, 2010 at 21:45 | comment | added | Qing Liu | Yes this is basically the same idea in different langages. Just a remark: if $c$ is considered as a variable, then $k(c)$ is not perfect even when $k$ is perfect because $k(c^{1/p})$ is always inseparable over $k(c)$. | |
| Oct 27, 2010 at 18:31 | history | edited | Terry Tao | CC BY-SA 2.5 |
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| Oct 27, 2010 at 18:24 | history | answered | Terry Tao | CC BY-SA 2.5 |