$\mathsf{FOL}^{(\infty)}$ is (always up to expressive strength) a sublogic of $\mathcal{L}_{\infty,\omega}^L=\mathcal{L}_{\infty,\omega}\cap L$. More generally, if $M$ is an inner model and $\mathcal{L}$ is a set-sized sublogic of $\mathcal{L}_{\infty,\omega}^M$ which is appropriately definable in $M$, then $\mathcal{L}'\subseteq\mathcal{L}^M_{\infty,\omega}$ as well.
$\mathsf{FOL}^{(\infty)}$ is strictly weaker than $\mathcal{L}_{\infty,\omega}^L$: if $(r_i)_{i\in\omega}$ are sufficiently mutually Cohen generic (say, generic over a countable elementary submodel of $L_{\omega_1}$), then the $\{<,\in\}$-structures $\omega\sqcup\{r_{2i}:i\in\omega\}$ and $\omega\sqcup\{r_{2i+1}: i\in\omega\}$ are $\mathsf{FOL}^{(\infty)}$-equivalent but not $\mathcal{L}_{\infty,\omega}^L$-equivalent.
The argument of the previous bulletpoint implies that the $\mathsf{FOL}^{(\infty)}$-definable relations on $(\omega;<)$ fall well short of the constructible ones. On the other hand, it's also easy to see that they reach well past the hyperarithmetic: the $\mathsf{FOL}^{(\omega_1^{CK})}$-definable relations are exactly the hyperarithmetic ones, and $\mathcal{O}$ is then $\mathsf{FOL}^{(\omega_1^{CK}+1)}$-definable since a computable linear order is a well-order iff it supports a hyperarithmetic jump sequence.
Finally, despite its clear weaknesses, for every countable structure $\mathfrak{A}$ the automorphism orbit relation on elements (or $n$-tuples for fixed $n$) of $\mathfrak{A}$ is $\mathsf{FOL}^{(\infty)}$-definable (this is just Scott's argument).