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Jan 8, 2023 at 14:32 vote accept Boby
Jan 7, 2023 at 16:20 comment added Vinícius Novelli @Boby I mean that $\mathcal{S}(\mathbb{R}) \subset C_0(\mathbb{R})$ is dense when $C_0(\mathbb{R})$ is endowed with the Banach norm $\|f\|_{C_0(\mathbb{R})}=\sup_{\mathbb{R}}|f|$. This has a standard proof using mollifiers, see here for example. For Riesz's theorem you can check Rudin's Real and Complex Analysis, chapter 6. For this proof in particular I don't know a reference, but it's so simple that I doubt you need one.
Jan 7, 2023 at 16:15 comment added Boby What do you mean 'by the density'. I couldn't follow that sentence fully. Also, do you have a good reference where I can find this proof. I want to cite something.
Jan 7, 2023 at 16:09 history answered Vinícius Novelli CC BY-SA 4.0