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S Jan 15, 2023 at 16:47 history bounty ended Tito Piezas III
S Jan 15, 2023 at 16:47 history notice removed Tito Piezas III
Jan 15, 2023 at 16:47 vote accept Tito Piezas III
Jan 12, 2023 at 4:57 answer added Tito Piezas III timeline score: 1
Jan 11, 2023 at 12:54 answer added Tom Ducat timeline score: 2
Jan 11, 2023 at 3:50 comment added Tito Piezas III @Somos Very interesting answer! For $p=11$, I'm trying to get $q^{m/660}$ so I've just asked a question now. Kindly see MO438244.
Jan 11, 2023 at 3:00 comment added Somos Perhaps modular forms is the reason. Consult my answer to MSE 3132502.
Jan 11, 2023 at 2:44 comment added Tito Piezas III @Somos I guess it is just a subjective remark. The numbers $q^{11/60}$ and $\frac{f(-q,\,-q^4)}{f(-q)}$ definitely don't look like radicals, but together become one. Same with $q^{61/168}$ and $\frac{f(-q,\,-q^6)}{f(-q^2)}$. Those are the unique powers of $q$ such that those Ramanujan theta quotients become radicals and I find it interesting, especially the high powers involved.
Jan 11, 2023 at 0:36 answer added Somos timeline score: 4
Jan 10, 2023 at 21:38 comment added Somos You may want to explain a bit what "where a,b surprisingly are radicals" means.
S Jan 9, 2023 at 22:02 history bounty started Tito Piezas III
S Jan 9, 2023 at 22:02 history notice added Tito Piezas III Canonical answer required
Jan 8, 2023 at 13:10 history edited Tito Piezas III CC BY-SA 4.0
Added link to Baruah's paper
Jan 8, 2023 at 5:40 history edited Tito Piezas III CC BY-SA 4.0
Clarified
Jan 8, 2023 at 4:06 history edited Tito Piezas III CC BY-SA 4.0
Added equivalent forms
Jan 7, 2023 at 18:12 history edited Tito Piezas III CC BY-SA 4.0
Added link to prior post.
Jan 7, 2023 at 13:55 history edited Tito Piezas III CC BY-SA 4.0
Corrected typo
Jan 7, 2023 at 13:45 history asked Tito Piezas III CC BY-SA 4.0