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Jan 9, 2023 at 18:58 vote accept xir
Jan 9, 2023 at 8:32 comment added David Loeffler @xir If you put together parts (iii), (iv), and (v) of the theorem from KLZ, then the Galois action drops out; but it isn't literally $R(1)$ that it lands in, it is $R(1 + \mathbf{k})$, where $\mathbf{k}$ is the canonical character $\mathbf{Z}_p^\times \to R^\times$ which specialises to $x \mapsto x^k$ at a weight $k$ point.
Jan 7, 2023 at 17:14 comment added xir found it in a different ohta paper!
Jan 7, 2023 at 17:13 answer added xir timeline score: 1
Jan 7, 2023 at 11:26 comment added Aphelli Oops, you’re right (I thought they talked about the Galois action, though…). Maybe in the Ohta paper that they cite, then?
Jan 7, 2023 at 1:07 comment added xir theorem 7.2.3(v) is very close to what I want, but it doesn't say anything about the Galois action!
Jan 6, 2023 at 22:27 comment added Aphelli My entry point would be Section 7 of Kings, Loeffler, Zerbes, “Rankin-Eisenstein classes and explicit reciprocity laws” (arxiv.org/abs/1503.02888) and references therein, but that may not be optimal. I merely happened to study that paper not too long ago.
Jan 6, 2023 at 22:10 history asked xir CC BY-SA 4.0