Timeline for Do cut-length-minimizing equidissections exist?
Current License: CC BY-SA 4.0
15 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| S Feb 3 at 22:00 | history | bounty ended | CommunityBot | ||
| S Feb 3 at 22:00 | history | notice removed | CommunityBot | ||
| Jan 26 at 22:53 | comment | added | Noah Schweber | @GerryMyerson Whoops! Since I have no idea what I had in mind, I've removed that (and fixed a typo). | |
| Jan 26 at 22:52 | history | edited | Noah Schweber | CC BY-SA 4.0 |
deleted 21 characters in body
|
| Jan 26 at 22:18 | comment | added | Gerry Myerson | "see e.g. here" is supposed to be a link, but it isn't one. | |
| S Jan 26 at 19:18 | history | bounty started | Noah Schweber | ||
| S Jan 26 at 19:18 | history | notice added | Noah Schweber | Draw attention | |
| S Jan 19, 2023 at 21:07 | history | bounty ended | CommunityBot | ||
| S Jan 19, 2023 at 21:07 | history | notice removed | CommunityBot | ||
| Jan 15, 2023 at 17:56 | comment | added | fedja | @MattF. That lemma is just false. Take a square with two (or twenty) Pinocchio noses on the top side and one big ear on the right side. Now take the same square with noses and the ear on the top and bottom sides respectively. You can relocate the ear in one cut but it is long, so it will be more beneficial to relocate all the noses and rotate the square, but it requires many cuts and it seems that with one cut allowed relocating the ear is optimal. | |
| Jan 13, 2023 at 12:03 | comment | added | Qise | I don't know how to justify it clearly, but it seems that for the example of equidissection in the wikipedia article you provided, every side of pieces that are on the inside of the square end up outside of the triangle. So it seems an equidissection is at least the perimeter of the triangle, ie. the one provided is optimal. | |
| S Jan 11, 2023 at 19:31 | history | bounty started | Noah Schweber | ||
| S Jan 11, 2023 at 19:31 | history | notice added | Noah Schweber | Draw attention | |
| Jan 4, 2023 at 14:26 | comment | added | user44143 | I think this needs a lemma that if there is a shorter dissection, then there is a shorter dissection without increasing the number of cut points or edges. A compactness argument would probably be enough after that. | |
| Jan 3, 2023 at 5:28 | history | asked | Noah Schweber | CC BY-SA 4.0 |