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Dec 30, 2022 at 20:41 comment added Joel David Hamkins But of course, being admissible/recursively inaccessible is mere KP, whereas $\alpha$ gives a ZFC model! So one should think of $\alpha$ as transcending that hiearchy.
Dec 30, 2022 at 20:21 comment added user44143 That is helpful, and with that I find another helpful answer from you also: mathoverflow.net/a/163835/44143
Dec 30, 2022 at 20:00 comment added Joel David Hamkins What would you want to know about it? This $\alpha$ is characterized by being the height of the minimal transitive model of ZFC. It is admissible, recursively inaccessible, etc. etc.
Dec 30, 2022 at 19:58 comment added user44143 What is known about the minimal $\alpha$?
Dec 30, 2022 at 16:47 comment added Joel David Hamkins Martin, I would like to thank you for your indefatigable efforts to improve MO with so many helpful edits, resourceful answers on meta, and everything else. Much appreciated!
Dec 30, 2022 at 16:00 history edited Martin Sleziak CC BY-SA 4.0
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Dec 30, 2022 at 11:56 comment added Asaf Karagila Yes, of course. I am just clarifying, since some people might not be up to date on technical jargon. :-)
Dec 30, 2022 at 11:52 comment added Joel David Hamkins Yes, agreed, and in fact, every model of ZFC has a model of ZFC inside it. mathoverflow.net/a/51786/1946 Meanwhile, the phrase "minimal model" is usually taken to refer to the minimal transitive model.
Dec 30, 2022 at 11:48 comment added Asaf Karagila Arguably there is no minimal model, because if we consider non-transitive models we can get "even smaller" models, in the sense that in $L_\alpha$ there is a model which is not even an $\omega$-model which is pointwise definable. No?
Dec 30, 2022 at 11:16 vote accept Zuhair Al-Johar
Dec 30, 2022 at 11:12 history edited Joel David Hamkins CC BY-SA 4.0
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Dec 30, 2022 at 11:06 history edited Joel David Hamkins CC BY-SA 4.0
added 1125 characters in body
Dec 30, 2022 at 10:53 history answered Joel David Hamkins CC BY-SA 4.0