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Dec 29, 2022 at 16:54 comment added Akira Thank you so much again. It seems the idea is to build a coarser topology that induces the same Borel $\sigma$-algebra. With coarser topology, we do not have enough open sets to approximate Borel sets.
Dec 29, 2022 at 16:45 history edited Iosif Pinelis CC BY-SA 4.0
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Dec 29, 2022 at 16:44 comment added Iosif Pinelis @Akira : I have added such a modification. However, at this point I don't have a counterexample with a $T_1$ topology over $X$, so that every single-point subset of $X$ be a closed set.
Dec 29, 2022 at 16:37 history edited Iosif Pinelis CC BY-SA 4.0
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Dec 29, 2022 at 16:35 vote accept Akira
Dec 29, 2022 at 16:35 comment added Akira Thank you so much for your answer. I got it. Can we have an example where there is some $A \in \tau$ such that $\mu (A) \in (0, \infty)$?
Dec 29, 2022 at 16:28 history answered Iosif Pinelis CC BY-SA 4.0