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Dec 29, 2022 at 16:48 comment added Giorgio Metafune I am using the results in DS I, Chapter 7, section 3. See in particular Theorem 18 (pag. 573 in my edition). In your case $\nu=1$.
Dec 29, 2022 at 15:36 comment added JZS Thank you for the answer. Would it be possible for you provide a more specific reference to the theory you use? Is there a particular chapter or section of Dunford-Schwartz that you refer to? The last piece I cannot show is that the kernel of $S$ is contained in the image of $A_0$, and for this I suppose I will need to see how $A_0S =0$ implies the resolvent has a simple pole.
Dec 26, 2022 at 21:56 history edited Giorgio Metafune CC BY-SA 4.0
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Dec 26, 2022 at 20:01 history answered Giorgio Metafune CC BY-SA 4.0