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Jan 5, 2023 at 3:56 vote accept Tim Campion
Jan 5, 2023 at 6:02
Jan 2, 2023 at 0:07 answer added Tim Campion timeline score: 1
Jan 1, 2023 at 10:41 comment added Z. M Do you expect any $\infty$-categorical version? Comprising $\infty$-topoi and prestable $\infty$-categories?
Jan 1, 2023 at 10:16 history edited Tim Campion CC BY-SA 4.0
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Dec 29, 2022 at 9:20 comment added Paul Taylor Regularity isn't enough, eg ${\mathbf{Set}}^{op}$. There is a pushout in $\mathbf{Set}$ using sets with 1, 2, 2 and 3 elements where the pullback has 4 elements, so $3\to 4$ is not epi in $\mathbf{Set}$ (mono in ${\mathbf{Set}}^{op}$).
Dec 25, 2022 at 3:29 history became hot network question
Dec 24, 2022 at 21:30 comment added Kevin Carlson Exactness isn’t enough: you can have pairs of subgroups with trivial intersection whose union is not the free product.
Dec 24, 2022 at 21:02 comment added Paul Taylor I asked this myself, including the directed case, but got no answer. From some other question I learned that Michael Barr had written about this in Springer LNM 1348. My application was to show when extensional well founded coalgebras have "overlapping unions" like sets ($\epsilon$-structures).
Dec 24, 2022 at 20:25 answer added godelian timeline score: 10
Dec 24, 2022 at 20:14 comment added Martin Brandenburg This comments seems to be an answer.
Dec 24, 2022 at 19:39 comment added godelian It suffices that $\mathcal{C}$ is a coherent category. The proof is mainly due to Joyal, and it appears e.g. in "Reyes, Gonzalo: From sheaves to logic - Studies in algebraic logic, M.A.A. studies in Math., vol. 9 (1974). The Elephant has also two different proofs, one using the internal language of the category.
Dec 24, 2022 at 19:26 history asked Tim Campion CC BY-SA 4.0