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Dec 22, 2022 at 18:10 comment added Justin_other_PhD @Ilya This is a good point! I have modified the question to focus on the case I'm most interested in, which is conditioning on $\sigma(Y_t)$ not $\sigma(\{Y_s\}_{0\le s\le t})$. Thanks for pointing this out.
Dec 22, 2022 at 18:09 history edited Justin_other_PhD CC BY-SA 4.0
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Dec 22, 2022 at 17:42 comment added SBF I am not an expert on continuous-time Markov processes, but I guess in discrete time if I have observations of $Y$ (being constructed dynamically using $Y$ and $X$), it is not enough for me to just know the latest value of $Y_t$ to get everything I can for the distribution of $X_t$, in most cases knowing the whole trajectory of $Y$ provides a strictly finer conditioning. I guess the same woule apply to continous-time case. Namely, $\Bbb P(X_t|\mathcal F_t^Y)$ is not a function of simply $Y_t$ and $t$.
S Dec 22, 2022 at 16:17 review First questions
Dec 22, 2022 at 16:49
S Dec 22, 2022 at 16:17 history asked Justin_other_PhD CC BY-SA 4.0