Skip to main content
15 events
when toggle format what by license comment
Jan 12, 2023 at 14:58 answer added S Argyros timeline score: 3
Jan 6, 2023 at 14:18 answer added S Argyros timeline score: 3
Jan 5, 2023 at 10:50 answer added S Argyros timeline score: 3
Dec 29, 2022 at 16:30 answer added S Argyros timeline score: 2
Dec 28, 2022 at 16:08 answer added S Argyros timeline score: 1
Dec 24, 2022 at 16:03 vote accept Nik Weaver
Dec 23, 2022 at 23:20 answer added Bill Johnson timeline score: 9
Dec 21, 2022 at 18:11 comment added Nik Weaver Hah! I didn't think of that.
Dec 21, 2022 at 17:23 comment added Christian Remling By the way, ending a question title with the word "closed" can be quite confusing for a second. (At least, you didn't write "[closed]".)
Dec 21, 2022 at 12:21 comment added S Argyros I mean Schauder basic sequences which by Mazur Theorem exist in any infinite dimensional Banach space.
Dec 21, 2022 at 12:16 comment added Nik Weaver My thought before posting was to do this with uniformly discrete sequences, but I didn't quite see why the intersection still had to be zero.
Dec 21, 2022 at 12:15 comment added Nik Weaver What is a "normalized basic sequence"? Do all Banach spaces have them?
Dec 21, 2022 at 11:52 comment added S Argyros A possible approach: First find a closed subspace $W$ such that $V_0 \cap W = 0$. If their sum is not closed then we finish. Otherwise find $ ( x_n )$ in $V_0$ and $( y_n ) $ in $W$ normalized basic sequences and set $ Z $ the closed subspace generated by $ ( x_n + 2^{-n } y_n )$. Then the sum of $V_0 $ and $Z $ is not closed.
Dec 21, 2022 at 4:59 history edited Nik Weaver CC BY-SA 4.0
added 6 characters in body
Dec 21, 2022 at 3:15 history asked Nik Weaver CC BY-SA 4.0