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Timeline for Automorphism-conjugacy

Current License: CC BY-SA 4.0

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Dec 10, 2022 at 7:06 comment added Ville Salo @RyleeLyman: Your answer is exactly what I was looking for, I am specifically interested in the automorphism problem. For some reason I only looked for a name of the equivalence relation, rather than searched for the problem directly. Probably this is also where I have encountered it.
Dec 10, 2022 at 6:52 comment added Ville Salo I did some rewording because of the close vote, because maybe the wording was not optimal, although I don't know whether the vote was about wording or content.
Dec 10, 2022 at 6:51 history edited Ville Salo CC BY-SA 4.0
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Dec 9, 2022 at 23:55 comment added LSpice Right, sorry. Actually, I only read the start of that comment, and didn't register the mention of the holomorph at the end. I will delete my comment.
Dec 9, 2022 at 21:27 comment added Ville Salo @LSpice: Yes, I mentioned that above. There are many characterizations of this property.
Dec 9, 2022 at 21:03 review Close votes
Dec 14, 2022 at 9:16
Dec 9, 2022 at 15:48 comment added Robbie Lyman In the context of Whitehead's algorithm for free groups, this usually goes by the name "automorphically equivalent"
Dec 9, 2022 at 11:15 comment added Ville Salo I agree that this is such a simple notion that it may not need a name. Nevertheless, maybe it has one. Some that I considered are "automorphic", "automorphically conjugate", "automorphism-conjugate", "outer-conjugate" (or something in that direction), "externally/holomorphically conjugate" (the elements are conjugate in the holomorph), some being more sensible than others. I'm fine with also not having a name, but this would help look for information on this.
Dec 9, 2022 at 11:11 comment added Ville Salo Yes, that's a possible roundabout way of rewording the definition.
Dec 9, 2022 at 11:01 comment added Carl-Fredrik Nyberg Brodda I don't quite understand. I guess you mean that $g, f$ are fixed group elements here, and that if there is an inner automorphism $\alpha$ mapping $g$ to $f$ then we say that $g$ and $f$ are conjugate -- but what if $\alpha$ is not inner? (I think this is your question). In that case, don't we just say that $g$ and $f$ are in the same automorphic orbit?
Dec 9, 2022 at 10:21 history edited Martin Sleziak
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Dec 9, 2022 at 10:04 history asked Ville Salo CC BY-SA 4.0