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Jeremy West
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How aboutStart with the collection of half-open intervals of the form $a \times [b, b+1)$$[a,a+1) \times 0$ where $a$ is any real number and $b$$a \geq 0$ is anyan integer? These are. This decomposes the positive $x$-axis into half-open vertical intervals that are disjoint and the plane is the union of all intervals of this form.

(Of course Now, you could turn this around to get intervalsfor every value of the form $[a,a+1) \times b$ where$0 < \theta < 2\pi$, decompose the ray whose angle with the positive $a$$x$-axis is an integer and $b$ is a real number, or any$\theta$ into half-open intervals with the open end of several other such configurations.)

I may have misunderstood the questioninterval placed at the endpoint nearest the origin.

How about the collection of intervals of the form $a \times [b, b+1)$ where $a$ is any real number and $b$ is any integer? These are half-open vertical intervals that are disjoint and the plane is the union of all intervals of this form.

(Of course, you could turn this around to get intervals of the form $[a,a+1) \times b$ where $a$ is an integer and $b$ is a real number, or any of several other such configurations.)

I may have misunderstood the question.

Start with the collection of half-open intervals of the form $[a,a+1) \times 0$ where $a \geq 0$ is an integer. This decomposes the positive $x$-axis into half-open intervals. Now, for every value of $0 < \theta < 2\pi$, decompose the ray whose angle with the positive $x$-axis is $\theta$ into half-open intervals with the open end of the interval placed at the endpoint nearest the origin.

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Post Undeleted by Jeremy West
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Jeremy West
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How about the collection of intervals of the form $a \times [b, b+1)$ where $a$ is any real number and $b$ is any integer? These are half-open vertical intervals that are disjoint and the plane is the union of all intervals of this form.

(Of course, you could turn this around to get intervals of the form $[a,a+1) \times b$ where $a$ is an integer and $b$ is a real number, or any of several other such configurations.)

I may have misunderstood the question.