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Dec 8, 2022 at 4:23 vote accept Hermi
Dec 8, 2022 at 2:19 answer added Iosif Pinelis timeline score: 2
Dec 7, 2022 at 21:14 comment added Fedor Petrov Well, if $u$ is chosen on the sphere, they indeed are iid (for any fixed $u$ the common distribution is the same)
Dec 7, 2022 at 19:27 history edited Hermi CC BY-SA 4.0
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Dec 7, 2022 at 18:38 history edited Hermi CC BY-SA 4.0
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Dec 7, 2022 at 18:38 comment added Hermi Does it seem that $X_i$ are still iid?
Dec 7, 2022 at 18:36 comment added Fedor Petrov Does not my proof still work? Now $X_i$'s are not independent, but what we actually need is that the distribution of $(X_1,\ldots,X_n)$ is symmetric.
Dec 7, 2022 at 18:27 history asked Hermi CC BY-SA 4.0