Skip to main content
9 events
when toggle format what by license comment
Dec 8, 2022 at 21:00 answer added Yegreg timeline score: 3
Dec 7, 2022 at 20:15 comment added David E Speyer A good test case would be to ask if a non-Desarguean projective plane has such a representation. en.wikipedia.org/wiki/Non-Desarguesian_plane
Dec 7, 2022 at 19:25 comment added David E Speyer According to mathoverflow.net/questions/55515/… , the answer is yes. So we are reduced to answering your question for $L^{\text{mod}}$.
Dec 7, 2022 at 17:38 comment added David E Speyer I wonder whether every lattice $L$ has a unique modular quotient $L^{\text{mod}}$ through which any map to a modular lattice factors?
Dec 7, 2022 at 17:19 history edited Yegreg CC BY-SA 4.0
added 20 characters in body
Dec 7, 2022 at 4:29 comment added Yegreg It would be OK, but having a lattice homomorphism onto $\{0 < 1\}$ seems quite far from being a necessary condition, even though it's sufficient.
Dec 7, 2022 at 3:46 comment added მამუკა ჯიბლაძე How unfaithful are you ready to be? Is, for example, something like $L\twoheadrightarrow\{0<1\}\hookrightarrow\operatorname{Sp}(V)$ OK?
S Dec 7, 2022 at 3:20 review First questions
Dec 7, 2022 at 7:11
S Dec 7, 2022 at 3:20 history asked Yegreg CC BY-SA 4.0