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Dec 6, 2022 at 20:39 vote accept Ehsan Shahoseini
Dec 6, 2022 at 13:49 answer added Franz Lemmermeyer timeline score: 2
Dec 5, 2022 at 23:11 comment added Ehsan Shahoseini Franz Lemmermeyer: Is it possible to explain more about your answer Professor? I didn't get the point I think. And also, what is $K(\mathfrak{p})$ here?
Dec 5, 2022 at 14:11 comment added Franz Lemmermeyer Ad 1: No; the extensions at the bottom might be unramified. Take $K = {\mathbb Q}(\sqrt{-6}\,)$ and ${\mathfrak p} = (2, \sqrt{-6})$.
Dec 3, 2022 at 20:10 history edited Ehsan Shahoseini CC BY-SA 4.0
added 2 characters in body
Dec 3, 2022 at 18:15 history edited LSpice CC BY-SA 4.0
`\smash`; `\operatorname`
Dec 3, 2022 at 16:24 history asked Ehsan Shahoseini CC BY-SA 4.0