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Nov 30, 2022 at 16:03 comment added LSpice Would you be willing to change "Euler quotient modulo $p$ two" to "Euler quotient $2$ modulo $p$"? It took me forever to parse the title, and I'm still not sure I got it right.
Nov 30, 2022 at 14:28 history edited YCor CC BY-SA 4.0
fixed typo
Nov 30, 2022 at 14:26 answer added Max Alekseyev timeline score: 4
Nov 30, 2022 at 1:37 comment added Gerry Myerson The "Euler quotient" $b(n)$ is $(2^{\phi(n)}-1)/n$, reduced modulo $n$. The alternating harmonic number $H'(m)$ is $\sum_1^m(-1)^{k+1}/k$.
Nov 29, 2022 at 17:02 history asked joro CC BY-SA 4.0