Timeline for Compilation of strategies to show that some constant is irrational
Current License: CC BY-SA 4.0
17 events
| when toggle format | what | by | license | comment | |
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| Dec 2, 2022 at 18:06 | comment | added | José Hdz. Stgo. | @SebastienPalcoux: Not to mention this one: mathoverflow.net/a/268632/1593 | |
| Dec 2, 2022 at 18:02 | answer | added | José Hdz. Stgo. | timeline score: 2 | |
| Nov 29, 2022 at 18:56 | comment | added | Sebastien Palcoux | @Pinteco: you may be interested in these posts: mathoverflow.net/q/377706/34538 mathoverflow.net/q/377925/34538 | |
| Nov 27, 2022 at 4:24 | history | became hot network question | |||
| Nov 26, 2022 at 20:28 | answer | added | Dror Speiser | timeline score: 8 | |
| Nov 26, 2022 at 6:26 | answer | added | Kevin O'Bryant | timeline score: 8 | |
| Nov 26, 2022 at 3:17 | history | edited | Pinteco | CC BY-SA 4.0 |
added 2 characters in body
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| Nov 25, 2022 at 19:46 | comment | added | Carl-Fredrik Nyberg Brodda | @AlexandreEremenko "I, Niven", on the other hand, was not quite the hit with his mathematical reader base that Asimov had hoped for. | |
| Nov 25, 2022 at 17:31 | comment | added | Stanley Yao Xiao | One of the more promising additions to this list which has unfortunately not yet bore fruit is to show that a given number is not a period (the ring of periods is countable and contains the set of algebraic numbers, and also some transcendental numbers like $\pi$. It is unknown if $e$ is a period or not). | |
| Nov 25, 2022 at 14:05 | comment | added | Alexandre Eremenko | And the polynomial can be called "Niven's polynomial", not "Ivan polynomial":-) | |
| Nov 25, 2022 at 14:01 | comment | added | Alexandre Eremenko | The author's name is Niven. Ivan is his first (given) name. The accepted way to mention him is either "Niven", or "I. Niven", or "Ivan Niven", but certainly not "Ivan":-) | |
| Nov 25, 2022 at 13:57 | comment | added | Wojowu | I feel like the question is pretty much asking for a summary of all of transcendental number theory. Of course it's still restricting to irrationality, but it still seems to me overly broad. | |
| Nov 25, 2022 at 13:54 | answer | added | JoshuaZ | timeline score: 8 | |
| Nov 25, 2022 at 13:30 | comment | added | JoshuaZ | Here's one that's a bit of a cheat: Show that the binary digits of the number are an uncomputable function. For example, take some reasonable enumeration of Turing machines T_n and let x_n be 1 when T_n halts on the blank tape and 0 when it does not. Then 0.x_1x_2x_3... is irrational. The objection here is that this gives you classes of irrationals, but does not in general give you any way to show a constant is irrational. (I don't know of any example where a constant already of interest was shown to be irrational this way, and almost all constants we care about are by nature computable.) | |
| Nov 25, 2022 at 11:35 | comment | added | Pinteco | I've fixed, thanks. | |
| Nov 25, 2022 at 11:35 | history | edited | Pinteco | CC BY-SA 4.0 |
added 135 characters in body
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| Nov 24, 2022 at 17:48 | history | asked | Pinteco | CC BY-SA 4.0 |