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Nov 24, 2022 at 19:38 comment added Adjoint Functor @Subhajit Jana I see...Thank you very much! I will try it!
Nov 24, 2022 at 19:34 comment added Subhajit Jana The above reference deals with the Fourier expansion with respect to the maximal unipotent (the 1+1+...+1 one). I believe the proof for the other unipotent subgroups can be similarly worked out (usually the maximal unipotent is the hardest case).
Nov 24, 2022 at 19:09 comment added Adjoint Functor @Subhajit Jana Thank you very much for your reply. I was considering the constant term of $E(g,s;\Phi,\eta)$ along any other (standard) parabolic subgroup of $GL_n$, not just the $(n-1,1)$ one.
Nov 24, 2022 at 18:56 history edited Adjoint Functor CC BY-SA 4.0
fix typo and give more details
Nov 24, 2022 at 18:34 comment added Subhajit Jana For any automorphic form $\phi$ in $\mathcal{A}^2(P)$ one can consider its constant term along any other parabolic $Q$, defined by $\int_{N_Q(F)\backslash N_Q(\mathbb{A})} \phi(n\cdot)$. For $E(g,s)$ the computation of the constant term is standard. You may look at section 3 at arxiv.org/abs/2012.07817.
Nov 24, 2022 at 18:01 history edited David Loeffler CC BY-SA 4.0
edited body
S Nov 24, 2022 at 17:30 review First questions
Nov 24, 2022 at 19:24
S Nov 24, 2022 at 17:30 history asked Adjoint Functor CC BY-SA 4.0